Tuesday, May 21, 2019
Chem Lab Mixtures Essay
In this research laboratory, a mixture of naphthalene (C10H8), common table salt (NaCl), and sea sand (SiO2) will be set-apart using the separation techniques in order to demonstrate the properties of mixtures and their ability to be separated by physical means. INTRODUCTIONThis lab was based on the separation of the components of a mixture. A mixture back be defined as a physical combination of two or more pure substances. Separation techniques are use to separate components that are not chemical substancely combined. All of these techniques involve changes in the physical state of a chemical compound rather than chemical changes.The three objectives in this lab were1. Learn the contrary separation techniques which include sublimation, extraction, decantation, filtration and evaporation. 2. Separate three components in a mixture using the separation techniques learned. 3. come across the down percentages of apiece of the three components present in a mixture.The 5 separatio n techniques are1) Sublimation involves the heat of a unattackable that passes directly from the straightforward human body into the gaseous phase. The reverse process where a gas goes into the solid phase is c all(prenominal)ed deposition or condensation. 2) Extraction involves using a solvent that selectively dismiss one or more components from a solid mixture. 3) Decantation involves the separation of a liquidness from insoluble solid sediment by carefully pou shout out the liquid from the solid without disturbing the solid. 4) Filtration involves separating a solid from a liquid through the use of a permeable material such as filter paper. The porous material allows the liquid to pass through it but not the solid. 5) Evaporation involves the process of heating a mixture in order to separate a volatile liquid in the form of a vapor, while the covering component dry.The mixtures that will be separated are naphthalene, common table salt, and sea sand. The separation of this mixture involves three feels which are heating the mixture to sublime the naphthalene, then dissolving the tablesalt with pissing to extract and evaporating water to recover dry NaCl and sand.To determine the percentage of each component in the mixture, this formula can be used. % component= grams of component isolatedgrams of initial consumePROCEDUREA. Preliminary Steps1. Obtain a clean, dry 150-mL beaker and iron out it to the nearest .001g. 2. Obtain a sample of the mixture from your instructor and carefully move out 2g of the mixture into the beaker. 3. Record the lading of the beaker with the mixture inside to nearest .001g and calculate the exact weight of the mixture by subtraction.B. Sublimation of Naphthalene1. Set up and do the sublimation in the hood.2. Place an evaporating dish with some ice on top of the beaker containing the mixture and place the beaker on a wire gauze with an iron ring and ring stand assembly. 3. Carefully heat the beaker with a Bunsen burner un til vapors appear in the beaker. A solid should collect on the underside of the evaporating dish. Continue heating for 10 minutes. 4. After 10 minutes, remove the Bunsen burner from under the beaker and then remove the evaporating disk from the beaker and collect the solid by scrapping it off the dish with a spatula onto a weighing paper. 5. Stir the contents of the beaker with a glass rod. Return the evaporating disk to the beaker and apply the heat again. Continue heating and scraping off solid until no more solid collects. 6. Weigh all the naphthalene collected and record it on the Report sheet to the nearest .001g. 7. Allow the beaker to cool and then weigh the beaker with the contained solid. Record the weight of the naphthalene sublimed by subtracting the weight of the beaker with remaining solid after sublimation from the weight of beaker 1 with original mixture.C. Separation of the Water Insoluble solid state1. Add 25mL of distilled water to the solid in the beaker. Heat gen tly andstir continuously for 5 min. 2. Weigh a second clean, dry 150-mL beaker with 2 or 3 boiling stones to nearest .001g and record its mass onto the data sheet. 3. Assemble the apparatus for gravity filtration as shown in Figure 3.4 4. Fold a military man of filter paper according to the technique in Figure 3.5. 5. Wet the filter paper with water and adjust the paper so that it lies flat on the glass of the funnel. 6. Position beaker 2 under the funnel and pour the mixture through the filter, first decanting most of the liquid into beaker 2 and then transferring the wet solid into the funnel. Collect all the liquid in beaker 2. 7. Rinse beaker 1 with 5-10-mL of water, pour over the residue in the funnel and add the liquid to the filtrate. *Repeat this step once more. 8. Place beaker 2 on the wire gauze with an iron ring and ring stand and heat using the Bunsen burner. As the wad of liquid is reduced, sodium chloride will appear. When the liquid is fully evaporated, allow the be aker to cool down. 9. Weigh the beaker, stones, and the solid residue to the nearest .001g. Calculate the weight of the recovered NaCl by subtraction.D. Drying the Sea Sand1. Weigh a third dry 150-mL beaker and transfer the sand from the filter paper to beaker 3. 2. Place beaker 3 with the sea sand on the wire gauze with an iron ring and ring stand and heat the sand to dryness. When dried, the sand should be freely flowing. 3. Allow the sand to cool to fashion temperature.4. Weigh the beaker and the sand to the nearest .001g.5. Calculate the weight of the recovered sand by subtraction.Results and DiscussionsIn this lab certain separation techniques were used and learned. When measuring the different amounts of the three components of the mixture, all measurements were based on significant figures. Thus, each certain digit plus one uncertain digit was included in all measurements. First, the sublimation of naphthalene was done by heating the mixture. The original weight of the napht halene collected was .070g and after sublimation theweight of naphthalene was .095g. Next, extraction was observed in separation of the water insoluble solid. The NaCl was separated from the SiO2 because of the solubility of NaCl in water and the insolubility of SiO2 in water. Solubility is the ability of a substance to dissolve when in the presence of a certain solvent. The NaCl was state to dissolve leaving only the insoluble sea sand in the beaker with the water. Filtration was overly observed in this experiment when the piece of filter paper was wetted and used for gravity filtration. The NaCl dissolved in the water, and by decantation, the process of separating a liquid from a solid by gently pouring the liquid from the solid so as not to disturb the solid, the NaCl solution was separated from the SiO2. Heating can cause substances to evaporate, which represents a change in state, so the water was evaporated from the NaCl, which left commode the solid NaCl. The amount of NaCl in the experiment was thrifty to be 0.822g, but the original sample with the weight of the beaker included actually weighed 65.001g.Then, the remaining component of the mixture, SiO2, was measured to be .927g once it had dried out. Originally the weight of the beaker and SiO2 was 67.078g. The comparison between the measured plenty of the three different substances in the mixture and the actual masses of the components proved that the substances of mixtures are able to separated, yet still retain their chemical and physical properties. After the components of the original sample were successfully separated, their weights were added together. The measured total weight of the three separate components of the recovered solids was 1.844g. The percentage buffer and percentage of all the substances was found. The percent yield was found by dividing the mass of the recovered solids by the mass of the mixture, then multiplying the answer by 100. The percentage yield for this experiment w as 88.314%.The makeup of that 88.314% is divided between naphthalene at 4.550%, NaCl at 39.368%, and sea sand at 44.397%. Sources of actus reus Ideally, the total percentage should have been 100%, because substances are neither created nor destroyed during these physical separation methods but due to minor errors such as faulty measurements, could have caused this slight deviation from the actual total. One possible lab error that may have affected this outcome is that some amount of naphthalene may have been lost to the air, thus resulting in a lower calculated mass. or because there was not enough ice on top. It can also be possible that accurate weightingmeasurements of the mixtures were not taken.Sample CalculationsWeight of naphthalene after sublimation =(weight of beaker 1 and mixture) ( weight of beaker 1 and solid after sublimation) (68.239)-(68.144)= .095gPercentage yield= (grams of solid recovered/grams of initial sample) x 100 Percentage of naphthalene (1.844/2.088)x1 00= 88.314%ConclusionsThe main concept I learned that was being applied and studied in this lab was that mixtures can be separated into their components by physical means. The purpose of the lab is to become familiar with the methods of separating substances from one another using decantation, extraction, and sublimation techniques. Mixtures occur in ordinary life in materials that are not uniform in composition. It is a combination of two or more substances. Mixtures are characterized by the fact that each of the substances in the mixture retains its chemical integrity, and that mixtures are separable into these components by physical means. In this lab, the starting point was a mixture of naphthalene, NaCl (sodium chloride), and SiO2 (sand). In the lab, it was determined that naphthalene can be sublimed from the mixture without having an effect on the other substances. It was also realized that NaCl is water soluble, while SiO2 is not water soluble. Since the SiO2 is not water so luble, is would remain after the water with NaCl was decanted.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.